Connecting...

This is a quick preview of the lesson. For full access, please Log In or Sign up.
For more information, please see full course syllabus of High School Physics
For more information, please see full course syllabus of High School Physics
High School Physics Newton's Third Law
Lecture Description
In a previous video we talked about how forces occur every day, but if that were true one would expect a foot to go through the ground every time someone took a step. Newton’s 3rd law prevents this by stating for every action there is an equal and opposite reaction; meaning that if a step is taken and a foot exerts a force on the ground, then the ground pushes up on the foot and thus prevents it from going through the ground. Always keep Newton’s 3 laws of motion in mind when going through this course as they will help you develop a physics-comprehendible mindset.
Bookmark & Share
Embed
Share this knowledge with your friends!
Copy & Paste this embed code into your website’s HTML
Please ensure that your website editor is in text mode when you paste the code.(In Wordpress, the mode button is on the top right corner.)
×
Since this lesson is not free, only the preview will appear on your website.
- - Allow users to view the embedded video in full-size.
Next Lecture
Previous Lecture
1 answer
Wed Mar 25, 2020 7:40 PM
Post by beihur777 on March 20, 2020
Hi,
In the 2nd example, after the first 0.2 seconds when astronaut throws the wrench, will he continue to accelerate at -0.5 m/s, or will he stay at the same velocity of -0.1 m/s?
Also, I have heard people use the term "newton second". Can you please explain what that means? I assume it means 1 newton of force applied for 1 second. But if that is true, will 5 newton seconds be 5 newtons of force applied for 1 second, 1 newton of force applied for 5 seconds, or something else entirely? Thanks in advance.
1 answer
Sat Jan 11, 2014 11:17 AM
Post by Jack Wilshere on January 11, 2014
Hello, I do not understand how the third example obeys the law of conservation of energy. Let's say the guy has a weight of 800 N and the height of the entire system is 3 m. At the top, the gravitational potential energy he has is 2400 J (800*3), yet the energy he spends going up is only 1200N (since the force that he exerts is only 1200 N and the distance traveled is 3m). What's going on?
1 answer
Sun Jul 28, 2013 9:05 PM
Post by enya zh on July 27, 2013
How come the moon doesn't drop into the Earth? What does it mean to have the moon in freefall?
Thanks!!!☺
3 answers
Fri May 24, 2013 2:08 PM
Post by Goutam Das on May 24, 2013
My questions may seem like unusual.Sorry about that.
1.I have no doubt about that the forces will be always equal, but the question is "why they are always equal"?
2.And What is the "source of that opposite force": Electromagnetic Force or something else?
3.Is there any "exception" of The 3rd Law?
1 answer
Fri May 24, 2013 11:15 AM
Post by Goutam Das on May 24, 2013
Hi Professor,
In the third example, why does pulling upwards with a pulley yield twice the force?
6 answers
Wed Nov 21, 2012 2:21 PM
Post by Tanveer Sehgal on November 20, 2012
Hey,
In the third example, there are two tensile forces acting in the positive direction and 1 in the negative direction. So why is it that we do not consider the force acting in the negative direction? The net force 2T-Fg. Why is not T-Fg?