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Post by varsha sharma on June 9, 2011

I want to master your notes and use them in my classroom and i want to work as an instructor in school of math and science.
Thanks,
Varsha

DeMoivre's Theorem

Main formulas:

  • If the complex number z is written in polar form z = reiθ , then we can find n-th powers as follows:
    zn = (reiθ )n = [r(cosθ + i sinθ )]n = rn(cosn θ + i sinn θ ) = rn ei  nθ
  • Every nonzero complex number has exactly n n-th roots.
  • We can find n-th roots as follows:
    n
     

    z
     
    =
    z[1/(n)] = (reiθ )[1/(n)]
    =
    [r(cosθ + i sinθ )][1/(n)]
    =
    r[1/(n)] ( cos θ + 2kπ

    n
    + i sin θ + 2kπ

    n
    )
    =
    r[1/(n)] ei  [(θ + 2kπ)/n]
    where k = 0,1,2,..., n− 1.

Example 1:

Convert the complex number z = − √ 3 + i into polar form and then use DeMoivre's Theorem to calculate z7.

Example 2:

Find all complex eighth roots of 16.

Example 3:

Find all complex cube roots of − 1.

Example 4:

Convert the complex number z = 2√ 2 − 2√ 2i into polar form and then use DeMoivre's Theorem to calculate z5.

Example 5:

Find all complex fourth roots of z = − 2 − 2√ 3i.
Give me another blank page here.

Convert the complex number w = − 1 + √3 i into polar form and then use DeMoivre's Theorem to calculate w5

  • DeMoivre's Theorem: zn = (re)n = [ r(cosθ+ isinθ) ]n = rn(cosnθ+ isinnθ) = rneinθ
  • r = √{x2 + y2}
  • r = √{( − 1)2 + (√3 )2} = 2
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • θ = arctan([(√3 )/( − 1)]) + π = − [(π)/3] + π = [(2π)/3]
  • w5 = (2e[(2π)/3]i)5 = 25e[(10π)/3]i = 32e[(4π)/3]i
  • 32(cos[(4π)/3] + isin[(4π)/3]) = 32[ ( − [1/2]) + i([( − √3 )/2]) ]

− 16 − 16√{3 i}

Convert the complex number w = − 4√3 + 4i into polar form and then use DeMoivre's Theorem to calculate w6

  • DeMoivre's Theorem: zn = (re)n = [ r(cosθ+ isinθ) ]n = rn(cosnθ+ isinnθ) = rneinθ
  • r = √{x2 + y2}
  • r = √{( − 4√3 )2 + (4)2} = 8
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • θ = arctan([4/( − 4√3 )]) + π = − [(π)/6] + π = [(5π)/6]
  • w6 = (8e[(5π)/6]i)6 = 86e[(30π)/6]i = 262144e5πi = 262144eπi
  • 262144(cosπ+ isinπ) = 262144[ ( − 1) + i(0) ]

− 262144

Convert the complex number w = − 2 + 2√{3 i} into polar form and then use DeMoivre's Theorem to calculate w7

  • DeMoivre's Theorem: zn = (re)n = [ r(cosθ+ isinθ) ]n = rn(cosnθ+ isinnθ) = rneinθ
  • r = √{x2 + y2}
  • r = √{( − 2)2 + (2√3 )2} = 4
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • θ = arctan([(2√3 )/( − 2)]) + π = − [(π)/3] + π = [(2π)/3]
  • w7 = (4e[(2π)/3]i)7 = 47e[(14π)/3]i = 16384e[(2π)/3]i
  • 16384(cos[(2π)/3] + isin[(2π)/3]) = 16384[ ( − [1/2]) + i([(√3 )/2]) ]

− 8192 + 8192√{3i}

Convert the complex number w = − 3√2 − 3√{2i} into polar form and then use DeMoivre's Theorem to calculate w4

  • DeMoivre's Theorem: zn = (re)n = [ r(cosθ+ isinθ) ]n = rn(cosnθ+ isinnθ) = rneinθ
  • r = √{x2 + y2}
  • r = √{( − 3√2 )2 + ( − 3√2 )2} = 6
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • θ = arctan([( − 3√2 )/( − 3√2 )]) + π = [(π)/4] + π = [(5π)/4]
  • w4 = (6e[(5π)/4]i)4 = 64e5πi = 1296e5πi = 1296eπi
  • 1296(cosπ+ isinπ) = 1296[ ( − 1) + i(0) ]

− 1296

Convert the complex number w = 4 + 4i into polar form and then use DeMoivre's Theorem to calculate w3

  • DeMoivre's Theorem: zn = (re)n = [ r(cosθ+ isinθ) ]n = rn(cosnθ+ isinnθ) = rneinθ
  • r = √{x2 + y2}
  • r = √{(4)2 + (4)2} = 4√2
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • θ = arctan([4/4]) = [(π)/4]
  • w3 = (4√2 e[(π)/4]i)4 = (4√2 )3e[(3π)/4]i = 128√2 e[(3π)/4]i
  • 128√2 (cos[3p/4] + isin[3p/4]) = 16384[ ( − [(√2 )/2]) + i([(√2 )/2]) ]

− 128 + 128i

Convert the complex number w = 2 − 2√{3 i} into polar form and then use DeMoivre's Theorem to calculate w4

  • DeMoivre's Theorem: zn = (re)n = [ r(cosθ+ isinθ) ]n = rn(cosnθ+ isinnθ) = rneinθ
  • r = √{x2 + y2}
  • r = √{(2)2 + ( − 2√3 )2} = 4
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • θ = arctan([( − 2√3 )/2]) = − [(π)/3] + 2π = [(5π)/3]
  • w4 = (4e[(5π)/3]i)4 = 44e[(20π)/3]i = 256e[(2π)/3]i
  • 256(cos[(2π)/3] + isin[(2π)/3]) = 256[ ( − [1/2]) + i([(√3 )/2]) ]

− 128 + 128√{3i}

Find all sixth roots of 1

  • There should be six different answers
  • DeMoivre's Theorem: z[1/n] = (re)[1/n] = [ r(cosθ+ isinθ) ][1/n] = r[1/n](cos[(θ+ 2kπ)/n] + isin[(θ+ 2kπ)/n]) = r[1/n]ei[(θ+ 2kπ)/n]
  • r = √{x2 + y2}
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • 1 + 0i
  • r = √{(1)2 + (0)2} = 1
  • θ = arctan([0/1]) = 0
  • z = 1ei0 ⇒ z[1/6] = 1[1/6](cos[(0 + 2kπ)/6] + isin[(0 + 2kπ)/6])

k [(θ+ 2kπ)/n] = [(0 + 2kπ)/6] = [(kπ)/3] cosα+i sinα Six Answers
0 0 1+0i 1
1 [(π)/3] [1/2] + [(√3 )/2]i [1/2] + [(√3 )/2]i
2 [(2π)/3] − [1/2] + [(√3 )/2]i − [1/2] + [(√3 )/2]i
3 π − 1 + 0i −1
4 [(4π)/3] − [1/2] − [(√3 )/2]i − [1/2] − [(√3 )/2]i

Find all fourth roots of - 4

  • There should be four different answers
  • DeMoivre's Theorem: z[1/n] = (re)[1/n] = [ r(cosθ+ isinθ) ][1/n] = r[1/n](cos[(θ+ 2kπ)/n] + isin[(θ+ 2kπ)/n]) = r[1/n]ei[(θ+ 2kπ)/n]
  • r = √{x2 + y2}
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • − 4 + 0i
  • r = √{( − 4)2 + (0)2} = 4
  • θ = arctan([0/( − 4)]) + π = π
  • z = 4e ⇒ z[1/4] = 1[1/4](cos[(π+ 2kπ)/4] + isin[(π+ 2kπ)/4])

k [(θ+ 2kπ)/n] = [(π+ 2kπ)/4] r[1/n](cosα+ isinα) Four Answers
0 [(π)/4] √2 ([(√2 )/2] + i[(√2 )/2]) 1+i
1 [(3π)/4] √2 ( − [(√2 )/2] + i[(√2 )/2]) −1+i
2 [(5π)/4] √2 ( − [(√2 )/2] + i( − [(√2 )/2]) ) −1−i
3 [(7π)/4] √2 ( [(√2 )/2] + i( − [(√2 )/2]) ) 1−i

Find all cube roots of 8

  • There should be three different answers
  • DeMoivre's Theorem: z[1/n] = (re)[1/n] = [ r(cosθ+ isinθ) ][1/n] = r[1/n](cos[(θ+ 2kπ)/n] + isin[(θ+ 2kπ)/n]) = r[1/n]ei[(θ+ 2kπ)/n]
  • r = √{x2 + y2}
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • 8 + 0i
  • r = √{(8)2 + (0)2} = 1
  • θ = arctan([0/8]) = 0
  • z = 8ei0 ⇒ z[1/3] = 8[1/3](cos[(0 + 2kπ)/3] + isin[(0 + 2kπ)/3])

k [(θ+ 2kπ)/n] = [(0 + 2kπ)/3] 2(cosα+ isinα) Three Answers
0 0 2(1 + 0i) 2
1 [(2π)/3] 2( − [1/2] + i[(√3 )/2] ) − 1 + √3 i
2 [(4π)/3] 2( − [1/2] − i[(√3 )/2] ) − 1 − √3 i

Find all cube roots of -125

  • There should be three different answers
  • DeMoivre's Theorem: z[1/n] = (re)[1/n] = [ r(cosθ+ isinθ) ][1/n] = r[1/n](cos[(θ+ 2kπ)/n] + isin[(θ+ 2kπ)/n]) = r[1/n]ei[(θ+ 2kπ)/n]
  • r = √{x2 + y2}
  • θ = arctan[y/x] if x is positive or θ = arctan[y/x] + π if x is negative
  • − 125 + 0i
  • r = √{( − 125)2 + (0)2} = 125
  • θ = arctan([0/( − 125)]) + π = π
  • z = 125e ⇒ z[1/3] = 125[1/3](cos[(π+ 2kπ)/3] + isin[(π+ 2kπ)/3])

k [(θ+ 2kπ)/n] = [(π+ 2kπ)/3] 5(cosα+ isinα) Three Answers
0 [(π)/3] 5( [1/2] + i[(√3 )/2] ) [5/2] + [(5√3 )/2]i
1 π 5( − 1 + i(0) ) −5
2 [(5π)/3] 5( [1/2] + i( − [(√3 )/2]) ) [5/2] − [(5√3 )/2]i

*These practice questions are only helpful when you work on them offline on a piece of paper and then use the solution steps function to check your answer.

Answer

DeMoivre's Theorem

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Mathematics: Trigonometry