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For more information, please see full course syllabus of AP Chemistry
For more information, please see full course syllabus of AP Chemistry
AP Chemistry Light
Lecture Description
Light is a form of electromagnetic radiation, energy that travels in waves. Waves with different frequencies and wavelengths have different amounts of energy, illustrated on the electromagnetic spectrum. Light travels at 2.99 x 10⁸ meters per second (c). This lecture explains the definitions of and how to calculate wavelengths and frequency and where different kinds of radiation fit into the electromagnetic spectrum. Energy is quantized; travels in discrete units based on Planck’s constant (6.626 x 10⁻³⁴ Joule-seconds) (E=h(ν)). These discrete units are particles called photons. This quantization indicates that light is both a wave and a particle—one of the foundational principles of quantum mechanics.
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2 answers
Last reply by: pak yin chin
Thu Feb 11, 2016 10:18 PM
Post by pak yin chin on January 20, 2016
Hi professor Hovasapian
I have question in my mid term exam cannot solve,
When sodium metal is bombard with ultraviolet radiation of wavelength 400nm,electrons with kinetic energy of 30.0 KJ/mod are ejected.What is the binding energy of sodium metal in KJ/mol and what is the wavelength of the enjected electrons?
thx
3 answers
Tue Jan 12, 2016 11:54 PM
Post by Tammy T on January 10, 2016
Hello professor Hovasapian,
-In ex 3, you said instead of thinking about the bullet as a particle travelling through space, we are thinking about the bullet as a wave (?=1.5x10-34 m) travelling through space. This was the part you mention something about not to confuse the Energy of the bullet as kinetic energy. -So I was playing around with the equation; I calculated Kinetic Energy of the bullet= 0.5mv^2= 2030.6J and the KE of electron to be 1.4x10^-15J.
-Then I calculate Energy from the wavelength of the bullet= h(velocity of bullet)/(wavelength of bullet)= 4192J. &Energy from wavelength of electron to be 2.28x10^-15J.
I dont know if it is correct calculate Energy from the wavelength like that. Supposed it is correct, what is the difference between KE and E calculated from wavelength? The numbers I shows that E calculated from wavelength is about 2 times KE.
2 answers
Last reply by: Jason Smith
Wed Nov 4, 2015 10:09 PM
Post by Jason Smith on November 1, 2015
Hi professor, this might be a silly question, but with science, you never know.
I understand that higher temperatures are associated with higher energy, and thus, higher frequency EM waves.
Does this mean that extremely cold objects emit radio waves? Since they're at the "lower energy" end of the EM spectrum? Likewise, does this mean that extremely hot objects emit gamma rays? Since they're at the "higher energy" end of the EM spectrum?
Thank you in advance professor.
1 answer
Wed Oct 28, 2015 12:36 AM
Post by Jason Smith on October 27, 2015
Hello professor, I have a question: is the energy associated with electromagnetic radiation the same energy associated with heat & work (from thermodynamics). I don't want to get too ahead of myself, I'm just curious :) Thanks!
1 answer
Tue Nov 25, 2014 2:27 AM
Post by Datevig Daghlian on November 24, 2014
Dear Professor Hovasapian,
As always, thank you very much for your lecture! My instructor told us that the speed of light is 3.00 X 10^8 m/s. Will this minute difference alter the results to the calculations I make on the AP Exam? Thank you and God bless!
George Daghlian
2 answers
Thu Nov 21, 2013 12:56 AM
Post by Tim Zhang on November 20, 2013
If molybdenum is irradiated with light of wavelength of 120 nm,
what is the maximum possible kinetic energy of the emitted
electrons?