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For more information, please see full course syllabus of Probability
For more information, please see full course syllabus of Probability
Probability Combining Events: Multiplication & Addition
Lecture Description
In the last lesson, we learned some of the basic terminology for probability and experiments about sample spaces and events. In this lesson, we are going to keep going with the combining events. We are going to learn how to build up more complicated events, using the union and intersection of events. We are also going to learn how to calculate the number of outcomes in events, in intersections, and unions of events, as well as some rules of multiplication and addition. This lesson also covers the conditional probability and independence, so you’ll learn some new and useful formulas.
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1 answer
Mon May 2, 2022 10:24 AM
Post by Pablo Daniel Avila on April 30, 2022
In Example I , solving by counting. 81 through a 100, that is 19 numbers. Why /B/= is 20?
2 answers
Sat Dec 1, 2018 5:55 PM
Post by Erico Lendzian on November 28, 2018
I also have a problem with this lecture. I get the viode just fine, but without sound.
1 answer
Mon Nov 19, 2018 12:56 PM
Post by Camilo Gomez on November 18, 2018
There is definitely something wrong with this video. All other lectures load and play without problem. I have rebooted, restarted, and so on, and cannot get it to play. I see that others have brought this issue as early as 2014! It is very disappointing to see that this has not been solved...
1 answer
Fri Aug 17, 2018 7:01 PM
Post by Chandrakala Bairagoni on August 8, 2018
Hi,
I see that there is a problem with
> Combining Events: Multiplication & Addition section starting from conditional probability and rest of the video is having the problem.
It looks this thread is running since very long but not yet resolved.
This is a very fundamental topic to understand the rest of the Probability. This is not good from the Educator perspective OR else refund the amount.
OR just add the quality recording on the site ASAP.
12 answers
Wed May 16, 2018 11:10 AM
Post by Shahriar Arfa-zanganeh on May 27, 2017
Hi Dr. William Murray,
I was wondering if there is anything wrong with this video or if there is a bug with it, as when I get to the conditional probability part of the video, the remaining amount of it turns into a black screen that does not go away. This effect does not seem to happen when I try playing other videos of yours, so I think it may just be this one that has this issue. Would be much appreciated if the issue is resolved, as you teach the material very well.
Thanks
1 answer
Tue Oct 4, 2016 11:59 AM
Post by Thuy Nguyen on October 1, 2016
Hi, about the combination meals where there are 12 main dishes, 4 drinks, and 3 desserts:
Why don't we divide out the 12*4*3 total meals by 3!? Won't some meals be counted more than once?
When do we divide out like the poker hand and when do we not like in this meal combination?
Thanks (smiles).
3 answers
Mon Nov 24, 2014 9:49 PM
Post by Jim McMahon on November 19, 2014
I cannot advance the lecture to a point that I am trying to jump to by clicking on the timeline. Is there a different way to advance the lecture to the desired section?
2 answers
Mon Jun 23, 2014 7:19 PM
Post by Sitora Muhamedova on June 21, 2014
In e.g # 5 calculate the conditional probability
you mentioned that the p(A∩B)=P(34)= 1/36
How come you ignore the other cases as far as I know it should be p(34,43) = 2/36.
Please explain this situation
1 answer
Mon Mar 31, 2014 11:02 PM
Post by Henry Thrift on March 28, 2014
I am not sure if you answered this question. I have completed this and wanted to check my work and also see the format you use to get the answer.
P[S∩M] 0.6 0.3 0.18
P[S∩M] = P[S|M]*P[M]
P[S∩M] = .30*.60
P[S∩M] = 0.18
P[S∩F] 0.35 0.4 0.14
P[S∩F] = P[S|F]*P[F]
P[S∩F] = .35*..40
P[S∩F] = 0.14
0.6 0.18 0.42
0.4 0.14 0.26
1 answer
Mon Mar 17, 2014 1:53 PM
Post by Henry Thrift on March 17, 2014
Do you use Joint and Marginal Probability Tables:
On Campus, 30% of the men smoke, and 35% of the women smoke. If our campus is 60% men and 40% women, construct the joint probability table.
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