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For more information, please see full course syllabus of Algebra 1
For more information, please see full course syllabus of Algebra 1
Algebra 1 Point Slope Form of an Equation
Lecture Description
Dr. Fraser covers the Point Slope Form of an Equation by first manipulating this new form into other more familiar equations before covering the representation of slope and a test point. This lesson ends with additional examples.
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2 answers
Last reply by: julius mogyorossy
Mon Aug 29, 2011 8:57 PM
Post by Mary Eastman on July 17, 2011
My answer I get for an equation I'm needing to write is: y-(9)=-2(x-5) i know this is in Point-Slope form but my instructor wants to see it in y=mx+b format. How do I do that? Thanks for any help I can get :D
0 answers
Post by james gordon on April 15, 2011
Re: Additional example 4
Express these 2 points (-6,-9) (-4,-8) in
point-slope form:
When I use the second point, (-4,-8), in my solution I get the correct answer y+8=1/2(x+4)
BUT
when I use the first point, (-6,-9), I get a different answer of y+9=1/2(x+6)
Is my second answer correct?
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Post by Matthew Chantry on January 1, 2011
When I follow along and work it out his way (getting rid of the fraction), I too get the final answer of y=(2/3)x+(17/3).
However, any other way I try it, I get y=(2/3)x=(23/3).
Any ideas?