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For more information, please see full course syllabus of Algebra 1
For more information, please see full course syllabus of Algebra 1
Algebra 1 Solving by Substitution
Lecture Description
In this video lesson you will learn how to solve systems of equations by substitution. By substituting, you can solve systems of equations without the more tedious method of graphing out all the equations. You will also understand the possible number of solutions which range from one to infinite and even no solutions.
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Post by Reuven Farchi on December 12, 2012
Love your teaching professor, it´s to the point and without talking down to you. Can you please tell me where can I find extra excercises to do in each chapter. Practice makes perfect and more so in math.
1 answer
Last reply by: jeffrey breci
Fri Jan 13, 2012 1:18 AM
Post by jeffrey breci on January 13, 2012
On example 2, I got the solution X=2, y=-1. Some how you got, x=12/7. How does -14x=-24 equal 12/7? I'm sure I won't get an answer, like everyone else on here. Collect that money people!
1 answer
Last reply by: Patryk Hebel
Sun Dec 5, 2010 8:51 AM
Post by John Barbour on November 11, 2010
The first example: 2(3y-)-6y=8 gives an answer of -2=8 Or did I do something wrong? Where are the professors? Mark asked a question on 12-11-09 and Sashka on 1-4-10 adn I still don't see an answer.
0 answers
Post by SASHKA YAKIMOVA on January 4, 2010
In Example 3, is there a reason why the second equation was picked over the first? How to determine which one to pick during an exam? Confusing...
0 answers
Post by Mark Mccraney on December 11, 2009
2:50 mark -- says the answer is nine halves, but is written correctly as 4/9