Connecting...

This is a quick preview of the lesson. For full access, please Log In or Sign up.
For more information, please see full course syllabus of Calculus AB
For more information, please see full course syllabus of Calculus AB
Calculus AB Rational Functions
Lecture Description
In this lesson, Professor John Zhu gives an introduction to rational functions. He teaches you how to graph rational functions and find asymptotes.
Bookmark & Share
Embed
Share this knowledge with your friends!
Copy & Paste this embed code into your website’s HTML
Please ensure that your website editor is in text mode when you paste the code.(In Wordpress, the mode button is on the top right corner.)
×
Since this lesson is not free, only the preview will appear on your website.
- - Allow users to view the embedded video in full-size.
Next Lecture
Previous Lecture
0 answers
Post by Nolan Zhang on April 9, 2015
If the degrees are the same, what I did was to divide the coefficients instead of their degrees. It worked out for a function like (17x^2-8x)/(4X^2+9), because if you divide their degrees, you will always get y=1 which appears not to be the case with the graph of that particular function. Please correct me if I'm wrong.(im talking about ex #3)
0 answers
Post by John Michael Musaazi on August 9, 2014
for the last example why is it (x-2)(x-5) instead of (x+2)(x-5)
1 answer
Last reply by: Adina Tung
Fri Apr 27, 2018 11:20 AM
Post by Julia Qiu on February 21, 2014
The graph of the first example that you draw is different from what I have done on the calculators. I think the behavior of your final function maybe have some problem.
0 answers
Post by John Michael Musaazi on January 8, 2014
How do you factor these equations and bring them down to a small number,am sorry i have not done math for a while.
0 answers
Post by Mirza Baig on December 18, 2013
I don't get it why do you guys look at your paper
2 answers
Mon Aug 12, 2013 8:52 PM
Post by Taylor Wright on August 11, 2013
In example 3:
Wouldn't there be another vertical asymptote at -4?
1 answer
Mon Aug 12, 2013 8:48 PM
Post by Taylor Wright on August 11, 2013
In example 2:
(4-x) does not equal -(x+4)
(4-x) = -(x-4) but -(x+4) = -4-x
2 answers
Last reply by: Angela Patrick
Sun Sep 1, 2013 2:27 PM
Post by Taylor Wright on August 11, 2013
How could there be a Horizontal Asymptote at y=0 if the point (1,0) is on the graph???