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For more information, please see full course syllabus of Multivariable Calculus
For more information, please see full course syllabus of Multivariable Calculus
Multivariable Calculus Tangent Plane
Lecture Description
In this lesson, we are going to talk about a very, very important topic called the tangent plane and it is exactly what you think it is. If you have a curve in space and you have some line, like in calculus when you did the derivative, you had the tangent to that curve - this is the analog, the next level up. If you have some surface in space, there is going to be some plane that is actually going to be tangent to it. It is going to touch the surface at some point. We are going to devise a way using the gradient to come up with an equation for that tangent plane.
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1 answer
Fri Aug 18, 2017 3:39 AM
Post by Ivan Burov on July 26, 2017
Dear Professor,
Does it matter that the equation given in the example is equal to 10? Or because it has no impact on differentiation it can be any constant? What is the physical meaning of 10 then?
Thanks!
Ivan
1 answer
Thu Jul 6, 2017 4:56 AM
Post by Tom Beatty on July 4, 2017
What am I missing in the last example: the pt (1,2) doesn't appear to lie on the curve f = xy^2+x^3=10?
f(1,2) = 1*2^2 + 1^3 = 5 not equal to 10
1 answer
Mon Jan 11, 2016 1:23 AM
Post by Jamal Tischler on January 8, 2016
I made a graph of a function in 2-space to show the gradient vector and the tangent line to the graph (using Desmos). Grab the blue dot and move it along the graph(only that way it will work), the purple segment will be the gradient vector.
https://www.desmos.com/calculator/foyfotfvjn
But why is it that the gradient that consist of all the partial derivatives will always be perpendicular to the curve ?
1 answer
Thu Nov 12, 2015 6:58 PM
Post by Ahmed Alzayer on November 12, 2015
Good Evening,
I have a problem that states the following:
Find an equation of the tangent plane to the graph of the given equation at the indicated point.
xy + yz + zx = 7 (1,-3,-5)
when I plug that point into the equation, it is not satisfied which means that point is
not on the plane, I thought that the given point has to be on the plane to work out the problem, can you please
clarify if there is something wrong with the given problem?
1 answer
Sat Oct 10, 2015 7:52 PM
Post by Hen McGibbons on October 10, 2015
My teacher derived the tangent plane using a taylor series. Is this another way of deriving the tangent plane using vectors? I'm assuming the way my teacher taught me can only be used for 2 space, and I'm thinking that this way can be used for any number of dimensions.
1 answer
Thu Jan 8, 2015 1:54 AM
Post by owais khan on January 6, 2015
in example 2, you made x~ = (x,y) why do you in some cases like example 1 make x~ = (x,y,z). ???
2 answers
Last reply by: Josh Winfield
Wed Feb 6, 2013 3:51 AM
Post by Josh Winfield on February 6, 2013
I always pause the video and attempt the example before watching you go through it.
This time i was way of mark with Example 2!
I saw in the question you wanted the Tangent line. So i thought whats the parametric representation of a line?
L=(P)+t(a)
P = Point of the line
a= direction Vector
I took P to = (1,2) given in the question and:
a to = the gradf(P) the direction Vector
and i got L= (1,2)+t(7,4)
L= (1+7t, 2+4t)
I clearly see that my approach is incorrect but where did i go wrong in what a thought was a logical approach???
One of the reasons i didn't think of x.n=p.n is because i thought this was a Plane equation, not a line equation?